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System Message

[00:00:00] *** Please note: All sessions are recorded for quality control. ***

sebastian (Customer)

[00:00:00] Linear equation

Murshid S (Tutor)

[00:00:05] Hello.

[00:00:25] Can you please write the question for me so I can better help you? Thanks :)

sebastian (Customer)

[00:00:57] hello and can I send it through a file ( no personal information is on the file)

Murshid S (Tutor)

[00:01:16] That will be fine.

sebastian (Customer)

[00:02:00] File Shared > Problem.jpeg

[00:02:06] it's number 11

Murshid S (Tutor)

[00:02:22] So first equation is 2x + y = 6

[00:02:28] and second equation is x - y = -3

[00:02:31] Is that correct?

sebastian (Customer)

[00:03:16] I keep getting (3,6) but the book says it should be (1,4)

[00:03:22] yess that's correct

Murshid S (Tutor)

[00:03:38] That is fine. Can you show me your work? So I can point out any errors if there are any?

sebastian (Customer)

[00:03:56] yess I can I'll draw it out

Murshid S (Tutor)

[00:04:08] Thanks.

[00:05:28] Hmm, I can see where the mistake is

[00:05:47] That should be a +

[00:05:59] Do you want me to show you why?

sebastian (Customer)

[00:07:35] well if I make x-y=-3 into y=x+z so that would make it -y=x-3 and you have to make why positive so you have to divide by negative one no?

Murshid S (Tutor)

[00:08:18] Close. Keep in mind that it is +x - y = -3.

[00:08:38] So when you want only -y on the left hand side, you SUBTRACT x from both sides.

[00:08:48] So you should have -y = -x - 3.

[00:09:01] And your step after that is correct, so it should be y = x + 3.

[00:09:11] Does that make sense? I can show it on the board.

[00:09:50] Are the steps clear?

sebastian (Customer)

[00:10:21] ooooo yess yess I see I though I just had to switch the side around but now it makes sense where it went wrong

Murshid S (Tutor)

[00:10:33] Excellent!

sebastian (Customer)

[00:10:30] thought*

Murshid S (Tutor)

[00:10:45] Just be careful with the signs and your math should be correct :)

[00:11:01] Do you want to work on the rest of the problem to see if you get the right answer?

sebastian (Customer)

[00:11:22] perfect thank you very much for your help, and no thank you I know what to do now

Murshid S (Tutor)

[00:11:58] Great! Thanks for choosing Tutor.com . You can always sign back in if you have any more questions! Good luck with your problem (Y)