Tutor.com The Definite Integral Session

May. 15, 2012

  • Poor
  • Fair
  • Average
  • Good
  • Excellent
  • Click to rate this Poor
  • Click to rate this Fair
  • Click to rate this Average
  • Click to rate this Good
  • Click to rate this Excellent


Session Transcript - Math - Calculus, 4/29/2012 10:17PM - Tutor.comSession Date: 4/29/2012 10:17PM
Length: 16.7 minute(s)
Subject: Math - Calculus


System Message
[00:00:00] *** Please note: All sessions are recorded for quality control. ***

Taewon (Customer)
[00:00:00] I need help with this!! [ File > http://lhh.tutor.com/SharedSessionFiles/332095a9-32dc-4629-95a5-ec0981bd62f9_2006_part_b_no8.jpg ]

Heather S (Tutor)
[00:00:17] hello and welcome to tutor.com

Taewon (Customer)
[00:01:11] hi

Heather S (Tutor)
[00:01:16] do you know how to get started?

Taewon (Customer)
[00:01:39] well I started out
[00:01:41] with the graph
[00:01:41] and
[00:01:44] I wasn't sure
[00:01:52] which part of the volume they wanted....

Heather S (Tutor)
[00:02:35] ok

Taewon (Customer)
[00:03:32] whatever..
[00:03:38] something like this

Heather S (Tutor)
[00:03:48] ok

Taewon (Customer)
[00:04:10] and said it was rotated in y- axis..
[00:04:26] so I was thing changing those functions to be x=

Heather S (Tutor)
[00:04:29] ok, so that's going to mean that you have to solve each of your equations for x right?

Taewon (Customer)
[00:05:29] and
[00:05:32] here I was stuck
[00:05:39] but I was thinking
[00:05:40] from
[00:05:42] -1 to 0
[00:05:45] since it is the y
[00:05:57] I'm talking about the range
[00:06:03] of the top and bottom limit

Heather S (Tutor)
[00:06:53] is that where it intersects?
[00:06:55] for y

Taewon (Customer)
[00:06:56] yes
[00:07:10] yes

Heather S (Tutor)
[00:08:15] so where I drew the pink is negative 1?
[00:08:29] so where is the other intersection point?
[00:08:33] there are 3 right?
[00:08:42] I think you are actually going to have to use 2 separate integrals

Taewon (Customer)
[00:08:48] oh,,,

Heather S (Tutor)
[00:09:05] I"m thinking about it....

Taewon (Customer)
[00:09:06] so..
[00:09:12] it would be this..
[00:11:13] is my function right?

Heather S (Tutor)
[00:11:53] I don't think your first part is right
[00:12:07] because wouldn't the Big R

Taewon (Customer)
[00:12:06] oh...

Heather S (Tutor)
[00:12:10] or outside radius
[00:12:16] still be the distance between the y axis

Taewon (Customer)
[00:12:21] so basically

Heather S (Tutor)
[00:12:25] and the (y+1)^1/3

Taewon (Customer)
[00:12:24] we are doubling
[00:12:28] the second part

Heather S (Tutor)
[00:12:36] between -2 and -1
[00:12:50] I think that is what is going to happen
[00:12:54] because there is symmetry here
[00:13:32] that should work

Taewon (Customer)
[00:14:23] this is wierd..
[00:14:24] I get 0

Heather S (Tutor)
[00:14:35] I got 1.676
[00:14:48] did you use your calculator

Taewon (Customer)
[00:14:50] yes

Heather S (Tutor)
[00:15:00] how did you enter it?

Taewon (Customer)
[00:15:32] oh
[00:15:34] found the mistake
[00:15:45] i did
[00:15:46] x
[00:15:48] not y

Heather S (Tutor)
[00:15:50] OK

Taewon (Customer)
[00:15:49] i get
[00:15:53] 1.6755

Heather S (Tutor)
[00:15:57]

Taewon (Customer)
[00:16:14] Right!
[00:16:18] Thanks for the help!
[00:16:23] Hope you have a great evening!

Heather S (Tutor)
[00:16:27] You're welcome
[00:16:29] and you too
[00:16:33] please fill out the survey
[00:16:36] on your way out

Taewon (Customer)
[00:16:36] ok

Heather S (Tutor)
[00:16:37] bye bye

Taewon (Customer)
[00:16:37] THnak!