Tutor.com Quadratic Functions Session

Jun. 29, 2012

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Session Transcript - Math - Algebra II, 6/19/2012 11:11PM - Tutor.comSession Date: 6/19/2012 11:11PM
Length: 20 minute(s)
Subject: Math - Algebra II


System Message
[00:00:00] *** Please note: All sessions are recorded for quality control. ***

Mitchell (Customer) (Customer)
[00:00:00] solve the equation by completing the square. a^2-14a+24=0
[00:00:09] Hi Therese

Therese B (Tutor)
[00:00:16] Hello
[00:00:29] Where are you in working on the problem?

Mitchell (Customer) (Customer)
[00:00:57] solve the problem but both answer is not equal to 0

Therese B (Tutor)
[00:01:27] Okay what do you do to set it up?

Mitchell (Customer) (Customer)
[00:02:03] Let me show you

Therese B (Tutor)
[00:02:11] Okay
[00:03:01] You are doing it great so far.

Mitchell (Customer) (Customer)
[00:03:41] ok I see my mistake, I did not do the perfect on my paper

Therese B (Tutor)
[00:03:54] Good
[00:05:09] Perfect!

Mitchell (Customer) (Customer)
[00:05:18] thank you

Therese B (Tutor)
[00:05:32] Okay anything else I can help you with?

Mitchell (Customer) (Customer)
[00:05:56] yes, can you help on Quadratic formula to solve the equation

Therese B (Tutor)
[00:06:04] Yes
[00:06:49] Do you know how to get started?

Mitchell (Customer) (Customer)
[00:06:59] no, not really

Therese B (Tutor)
[00:07:21] First you will need to have the whole equation set equal to zero.
[00:07:40] So do you know what I mean and how to do that?

Mitchell (Customer) (Customer)
[00:07:43] yes

Therese B (Tutor)
[00:07:51] Good

Mitchell (Customer) (Customer)
[00:08:09] is that right?

Therese B (Tutor)
[00:08:15] Correct
[00:08:33] Now do you know your quadratic formula?

Mitchell (Customer) (Customer)
[00:08:44] no

Therese B (Tutor)
[00:09:39] Once you have the quadratic formula then you will sub in your values of a, b, and c from the equation.
[00:10:01] Are you stuck from there with your writing of the formula?

Mitchell (Customer) (Customer)
[00:10:09] ok
[00:10:14] I found the formula

Therese B (Tutor)
[00:10:33] What you are missing is the square root of b^2 -4ac
[00:12:00] Great now you need to simplify it.
[00:13:26] Looks great.
[00:13:48] Have you worked with imaginary complex numbers

Mitchell (Customer) (Customer)
[00:13:55] yes

Therese B (Tutor)
[00:14:21] So your next step would be writing it in terms of i
[00:15:02] Almost - your 15 would still be under the radical.

Mitchell (Customer) (Customer)
[00:15:11] ok

Therese B (Tutor)
[00:15:44] Your non-real solutions will always be a conjugate pair.

Mitchell (Customer) (Customer)
[00:15:57] ok
[00:16:15] is this the solution?

Therese B (Tutor)
[00:17:12] 15 still under your radical

Mitchell (Customer) (Customer)
[00:17:19] ok

Therese B (Tutor)
[00:17:51] And sometimes it will be written out like that for the real and non-real parts of the complex number.
[00:18:18] Either way is correct as long as you have that square root of 15.

Mitchell (Customer) (Customer)
[00:18:54] ok, thank you again for your assistance

Therese B (Tutor)
[00:19:13] Are you clear now?

Mitchell (Customer) (Customer)
[00:19:18] yes

Therese B (Tutor)
[00:19:39] Have a great evening and please complete our survey. Thanks for using us.

Mitchell (Customer) (Customer)
[00:19:53] have great evening too!