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System Message

[00:00:00] *** Please note: All sessions are recorded for quality control. ***

sydney (Customer)

[00:00:00] Simplify this

Christopher B (Tutor)

[00:00:07] Welcome to Tutor.com ! How can I help you today?

sydney (Customer)

[00:00:14] hello

[00:00:31] I need help simplifying this

Christopher B (Tutor)

[00:00:59] Alright, please give me one second to look at it.

sydney (Customer)

[00:01:56]

[00:02:01] kay

Christopher B (Tutor)

[00:03:26] Alright.

[00:03:58] So any thoughts on where we can start?

sydney (Customer)

[00:04:09] None at all... :\

Christopher B (Tutor)

[00:04:17] That's fine.

[00:04:42] Let's forget about the exponent for right now and just worry about what is in front of the parentheses.

sydney (Customer)

[00:04:54] alright.

Christopher B (Tutor)

[00:05:05] We don't like having x's and y's in both the numerator and denominator so how can we get there just to be one x term and one y term?

sydney (Customer)

[00:05:35] umm, not sure?

Christopher B (Tutor)

[00:07:29] So what we see here is that we have terms raised to powers.
So our first thought should be to attempt to apply our Laws of Exponents.

[00:07:36] Which law do you think we should apply?

sydney (Customer)

[00:07:52] umm, we need the
denominators alike, don;t we?

Christopher B (Tutor)

[00:08:20] What do you mean?

sydney (Customer)

[00:08:50] The denominators have to be
the same on the top and
bottom exponents to be able
to do anything?

Christopher B (Tutor)

[00:09:49] Well we can change that eventually.
But what we are going to do in terms of rule?

sydney (Customer)

[00:09:57] I have no clue

Christopher B (Tutor)

[00:11:32] Well when we have
a quotient like this we know we can use this law:

sydney (Customer)

[00:11:44] Oh yeah!

Christopher B (Tutor)

[00:12:00] That seems familiar right?

sydney (Customer)

[00:12:14] somewhat, yes

Christopher B (Tutor)

[00:13:05] Ok, so when we have the same base in the numerator and denominator we can subtract the powers.

[00:13:41] So can't we do that with the terms we have for the problem we are working on?

sydney (Customer)

[00:13:48] yes, true

[00:13:50] they arent alike

Christopher B (Tutor)

[00:14:56] Well not right now, but we can change that.

[00:15:07] So this is what our problem would change to:

[00:15:40] Does that make sense?

sydney (Customer)

[00:15:57] so just subtract the exponents
and leave x and y where tehy
are?

[00:16:27] x would have an exponent of
1/6

[00:16:50] and y is a negative 5/12

Christopher B (Tutor)

[00:17:04] yes

sydney (Customer)

[00:17:05] but can;t you move the -5/12
to the bottom?

Christopher B (Tutor)

[00:17:07] Exactly

sydney (Customer)

[00:17:15] and reverse the negative?

Christopher B (Tutor)

[00:17:19] So what would that look like on the whiteboard?

sydney (Customer)

[00:17:52] ?

Christopher B (Tutor)

[00:17:55] Perfect

[00:18:05] Now lets go back to our exponent of 6.

sydney (Customer)

[00:18:23] now multiply by the exponent
of 6

[00:18:24] ?

Christopher B (Tutor)

[00:19:44] Excellent, exactly right.

[00:19:53] So what would the solution look like?

sydney (Customer)

[00:21:14] um that?

Christopher B (Tutor)

[00:21:19] Awesome.

[00:21:40] So what we did here was we used a couple of the Laws of Exponents to simplify this expression.

[00:21:56] Do you have any questions about what we did?

sydney (Customer)

[00:22:01] No, not at all!

[00:22:04] I understand it now!

[00:22:07] Thanks soooo much!

Christopher B (Tutor)

[00:22:11] Great.

[00:22:17] No problem, that's what I'm here for.

sydney (Customer)

[00:22:22] I can finish my homework
now. You were a lot of help

[00:22:31] Have a nice night sir!

Christopher B (Tutor)

[00:22:41] You too. Please fill out the survey afterwards.