Tutor.com Exponential and Logarithmic Functions Session

May. 24, 2012

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Session Transcript - Math - Algebra II, 5/15/2012 9:06PM - Tutor.comSession Date: 5/15/2012 9:06PM
Length: 22.8 minute(s)
Subject: Math - Algebra II


System Message
[00:00:00] *** Please note: All sessions are recorded for quality control. ***

sydney (Customer)
[00:00:00] Simplify this

Christopher B (Tutor)
[00:00:07] Welcome to Tutor.com ! How can I help you today?

sydney (Customer)
[00:00:14] hello
[00:00:31] I need help simplifying this

Christopher B (Tutor)
[00:00:59] Alright, please give me one second to look at it.

sydney (Customer)
[00:01:56]
[00:02:01] kay

Christopher B (Tutor)
[00:03:26] Alright.
[00:03:58] So any thoughts on where we can start?

sydney (Customer)
[00:04:09] None at all... :\

Christopher B (Tutor)
[00:04:17] That's fine.
[00:04:42] Let's forget about the exponent for right now and just worry about what is in front of the parentheses.

sydney (Customer)
[00:04:54] alright.

Christopher B (Tutor)
[00:05:05] We don't like having x's and y's in both the numerator and denominator so how can we get there just to be one x term and one y term?

sydney (Customer)
[00:05:35] umm, not sure?

Christopher B (Tutor)
[00:07:29] So what we see here is that we have terms raised to powers. So our first thought should be to attempt to apply our Laws of Exponents.
[00:07:36] Which law do you think we should apply?

sydney (Customer)
[00:07:52] umm, we need the denominators alike, don;t we?

Christopher B (Tutor)
[00:08:20] What do you mean?

sydney (Customer)
[00:08:50] The denominators have to be the same on the top and bottom exponents to be able to do anything?

Christopher B (Tutor)
[00:09:49] Well we can change that eventually. But what we are going to do in terms of rule?

sydney (Customer)
[00:09:57] I have no clue

Christopher B (Tutor)
[00:11:32] Well when we have a quotient like this we know we can use this law:

sydney (Customer)
[00:11:44] Oh yeah!

Christopher B (Tutor)
[00:12:00] That seems familiar right?

sydney (Customer)
[00:12:14] somewhat, yes

Christopher B (Tutor)
[00:13:05] Ok, so when we have the same base in the numerator and denominator we can subtract the powers.
[00:13:41] So can't we do that with the terms we have for the problem we are working on?

sydney (Customer)
[00:13:48] yes, true
[00:13:50] they arent alike

Christopher B (Tutor)
[00:14:56] Well not right now, but we can change that.
[00:15:07] So this is what our problem would change to:
[00:15:40] Does that make sense?

sydney (Customer)
[00:15:57] so just subtract the exponents and leave x and y where tehy are?
[00:16:27] x would have an exponent of 1/6
[00:16:50] and y is a negative 5/12

Christopher B (Tutor)
[00:17:04] yes

sydney (Customer)
[00:17:05] but can;t you move the -5/12 to the bottom?

Christopher B (Tutor)
[00:17:07] Exactly

sydney (Customer)
[00:17:15] and reverse the negative?

Christopher B (Tutor)
[00:17:19] So what would that look like on the whiteboard?

sydney (Customer)
[00:17:52] ?

Christopher B (Tutor)
[00:17:55] Perfect
[00:18:05] Now lets go back to our exponent of 6.

sydney (Customer)
[00:18:23] now multiply by the exponent of 6
[00:18:24] ?

Christopher B (Tutor)
[00:19:44] Excellent, exactly right.
[00:19:53] So what would the solution look like?

sydney (Customer)
[00:21:14] um that?

Christopher B (Tutor)
[00:21:19] Awesome.
[00:21:40] So what we did here was we used a couple of the Laws of Exponents to simplify this expression.
[00:21:56] Do you have any questions about what we did?

sydney (Customer)
[00:22:01] No, not at all!
[00:22:04] I understand it now!
[00:22:07] Thanks soooo much!

Christopher B (Tutor)
[00:22:11] Great.
[00:22:17] No problem, that's what I'm here for.

sydney (Customer)
[00:22:22] I can finish my homework now. You were a lot of help
[00:22:31] Have a nice night sir!

Christopher B (Tutor)
[00:22:41] You too. Please fill out the survey afterwards.